C24H30N6O16Rh2
1 compound has this formula on CompoundList.
- Molar mass
- 864.35g/mol
- Monoisotopic mass
- 863.9828Da
- Atoms
- 78
- Elements
- 5
The formula C24H30N6O16Rh2 describes a molecule made of 24 carbon atoms, 30 hydrogen atoms, 6 nitrogen atoms, 16 oxygen atoms and 2 rhodium atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 2433.35%12.011 × 24 = 288.264 g/mol
- H Hydrogen × 303.50%1.008 × 30 = 30.240 g/mol
- N Nitrogen × 69.72%14.007 × 6 = 84.042 g/mol
- O Oxygen × 1629.62%15.999 × 16 = 255.984 g/mol
- Rh Rhodium × 223.81%102.91 × 2 = 205.820 g/mol
Compounds with the formula C24H30N6O16Rh2
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
![Rhodium, bis(acetonitrile)tetrakis[mu-[methyl 2-(oxo-kappaO)-4-oxazolidinecarboxylato-kappaN3]]di-, (Rh-Rh), stereoisomer chemical structure, C24H30N6O16Rh2, CAS 167693-36-9](/s/AKXBDWBPALTEEI-UHFFFAOYSA-J.svg)
Frequently asked questions
What is the molar mass of C24H30N6O16Rh2?
The molar mass of C24H30N6O16Rh2 is 864.35 g/mol, calculated from standard atomic weights for 24 carbon atoms, 30 hydrogen atoms, 6 nitrogen atoms, 16 oxygen atoms and 2 rhodium atoms. The monoisotopic mass is 863.9828 Da.
How many compounds have the formula C24H30N6O16Rh2?
CompoundList lists 1 compound with the molecular formula C24H30N6O16Rh2, including Rhodium, bis(acetonitrile)tetrakis[mu-[methyl 2-(oxo-kappaO)-4-oxazolidinecarboxylato-kappaN3]]di-, (Rh-Rh), stereoisomer. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.