C24H31ClO7
5 compounds have this formula on CompoundList.
- Molar mass
- 466.95g/mol
- Monoisotopic mass
- 471.2072Da
- Atoms
- 63
- Elements
- 4
- Rings plus double bonds
- 9
The formula C24H31ClO7 describes a molecule made of 24 carbon atoms, 31 hydrogen atoms, 1 chlorine atom and 7 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 2461.73%12.011 × 24 = 288.264 g/mol
- H Hydrogen × 316.69%1.008 × 31 = 31.248 g/mol
- Cl Chlorine × 17.59%35.45 × 1 = 35.450 g/mol
- O Oxygen × 723.98%15.999 × 7 = 111.993 g/mol
Compounds with the formula C24H31ClO7
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 5 of 5 compounds
![Chloromethyl 17-ethoxycarbonyloxy-11-hydroxy-10,13-dimethyl-3-oxo-7,8,9,11,12,14,15,16-octahydro-6H-cyclopenta[a]phenanthrene-17-carboxylate chemical structure, C24H31ClO7, CAS 1156833-32-7](/s/DMKSVUSAATWOCU-UHFFFAOYSA-N.svg)
Frequently asked questions
What is the molar mass of C24H31ClO7?
The molar mass of C24H31ClO7 is 466.95 g/mol, calculated from standard atomic weights for 24 carbon atoms, 31 hydrogen atoms, 1 chlorine atom and 7 oxygen atoms. The monoisotopic mass is 471.2072 Da.
How many compounds have the formula C24H31ClO7?
CompoundList lists 5 compounds with the molecular formula C24H31ClO7, including Loteprednol etabonate, Glystrophan, Lanproston. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C24H31ClO7?
C24H31ClO7 has a degree of unsaturation of 9. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.