C25H25IO10
2 compounds have this formula on CompoundList.
- Molar mass
- 612.37g/mol
- Monoisotopic mass
- 612.0492Da
- Atoms
- 61
- Elements
- 4
- Rings plus double bonds
- 13
The formula C25H25IO10 describes a molecule made of 25 carbon atoms, 25 hydrogen atoms, 1 iodine atom and 10 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 2549.04%12.011 × 25 = 300.275 g/mol
- H Hydrogen × 254.12%1.008 × 25 = 25.200 g/mol
- I Iodine × 120.72%126.9 × 1 = 126.900 g/mol
- O Oxygen × 1026.13%15.999 × 10 = 159.990 g/mol
Compounds with the formula C25H25IO10
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 2 of 2 compounds
Frequently asked questions
What is the molar mass of C25H25IO10?
The molar mass of C25H25IO10 is 612.37 g/mol, calculated from standard atomic weights for 25 carbon atoms, 25 hydrogen atoms, 1 iodine atom and 10 oxygen atoms. The monoisotopic mass is 612.0492 Da.
How many compounds have the formula C25H25IO10?
CompoundList lists 2 compounds with the molecular formula C25H25IO10, including Moflomycin, 7-(4,5-Dihydroxy-3-iodo-6-methyloxan-2-yl)oxy-6,9,11-trihydroxy-9-(hydroxymethyl)-8,10-dihydro-7H-tetracene-5,12-dione. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C25H25IO10?
C25H25IO10 has a degree of unsaturation of 13. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.