CompoundList
Molecular formula

C25H31N5O

9 compounds have this formula on CompoundList.

Molar mass
417.56g/mol
Monoisotopic mass
417.2529Da
Atoms
62
Elements
4
Rings plus double bonds
13

The formula C25H31N5O describes a molecule made of 25 carbon atoms, 31 hydrogen atoms, 5 nitrogen atoms and 1 oxygen atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 2571.91%
    12.011 × 25 = 300.275 g/mol
  • H Hydrogen × 317.48%
    1.008 × 31 = 31.248 g/mol
  • N Nitrogen × 516.77%
    14.007 × 5 = 70.035 g/mol
  • O Oxygen × 13.83%
    15.999 × 1 = 15.999 g/mol
Look up another formula

Compounds with the formula C25H31N5O

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 9 of 9 compounds

Frequently asked questions

What is the molar mass of C25H31N5O?

The molar mass of C25H31N5O is 417.56 g/mol, calculated from standard atomic weights for 25 carbon atoms, 31 hydrogen atoms, 5 nitrogen atoms and 1 oxygen atom. The monoisotopic mass is 417.2529 Da.

How many compounds have the formula C25H31N5O?

CompoundList lists 9 compounds with the molecular formula C25H31N5O, including 1-Cyclohexyl-3-[2-(1-phenylethyl)-3,4-dihydro-1H-pyrazino[1,2-a]benzimidazol-8-yl]urea, TZB-30878 metabolite M5, 2-Pyrimidinamine, N-cyclohexyl-4-[3-phenyl-5-(1-piperidinylmethyl)-4-isoxazolyl]-. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C25H31N5O?

C25H31N5O has a degree of unsaturation of 13. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.