C25H39F
1 compound has this formula on CompoundList.
- Molar mass
- 358.58g/mol
- Monoisotopic mass
- 358.3036Da
- Atoms
- 65
- Elements
- 3
- Rings plus double bonds
- 6
The formula C25H39F describes a molecule made of 25 carbon atoms, 39 hydrogen atoms and 1 fluorine atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 2583.74%12.011 × 25 = 300.275 g/mol
- H Hydrogen × 3910.96%1.008 × 39 = 39.312 g/mol
- F Fluorine × 15.30%18.998 × 1 = 18.998 g/mol
Compounds with the formula C25H39F
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
![1-Fluoro-4-[2-[(trans,trans)-4a(2)-pentyl[1,1a(2)-bicyclohexyl]-4-yl]ethyl]benzene chemical structure, C25H39F, CAS 116020-40-7](/s/XKRNUBKDEPFDCX-UHFFFAOYSA-N.svg)
Frequently asked questions
What is the molar mass of C25H39F?
The molar mass of C25H39F is 358.58 g/mol, calculated from standard atomic weights for 25 carbon atoms, 39 hydrogen atoms and 1 fluorine atom. The monoisotopic mass is 358.3036 Da.
How many compounds have the formula C25H39F?
CompoundList lists 1 compound with the molecular formula C25H39F, including 1-Fluoro-4-[2-[(trans,trans)-4a(2)-pentyl[1,1a(2)-bicyclohexyl]-4-yl]ethyl]benzene. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C25H39F?
C25H39F has a degree of unsaturation of 6. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.