CompoundList
Molecular formula

C27H23N5O4S

7 compounds have this formula on CompoundList.

Molar mass
513.57g/mol
Monoisotopic mass
513.1471Da
Atoms
60
Elements
5
Rings plus double bonds
19

The formula C27H23N5O4S describes a molecule made of 27 carbon atoms, 23 hydrogen atoms, 5 nitrogen atoms, 4 oxygen atoms and 1 sulfur atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 2763.15%
    12.011 × 27 = 324.297 g/mol
  • H Hydrogen × 234.51%
    1.008 × 23 = 23.184 g/mol
  • N Nitrogen × 513.64%
    14.007 × 5 = 70.035 g/mol
  • O Oxygen × 412.46%
    15.999 × 4 = 63.996 g/mol
  • S Sulfur × 16.24%
    32.06 × 1 = 32.060 g/mol
Look up another formula

Compounds with the formula C27H23N5O4S

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 7 of 7 compounds

Frequently asked questions

What is the molar mass of C27H23N5O4S?

The molar mass of C27H23N5O4S is 513.57 g/mol, calculated from standard atomic weights for 27 carbon atoms, 23 hydrogen atoms, 5 nitrogen atoms, 4 oxygen atoms and 1 sulfur atom. The monoisotopic mass is 513.1471 Da.

How many compounds have the formula C27H23N5O4S?

CompoundList lists 7 compounds with the molecular formula C27H23N5O4S, including N-(4-Acetamidophenyl)-2-{[3-(2-methoxyphenyl)-4-oxo-3H,4H,5H-pyrimido[5,4-b]indol-2-yl]sulfanyl}acetamide, Egfr-IN-59, hCA I-IN-1. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C27H23N5O4S?

C27H23N5O4S has a degree of unsaturation of 19. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.