C27H29FN4O
4 compounds have this formula on CompoundList.
- Molar mass
- 444.55g/mol
- Monoisotopic mass
- 444.2325Da
- Atoms
- 62
- Elements
- 5
- Rings plus double bonds
- 15
The formula C27H29FN4O describes a molecule made of 27 carbon atoms, 29 hydrogen atoms, 1 fluorine atom, 4 nitrogen atoms and 1 oxygen atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 2772.95%12.011 × 27 = 324.297 g/mol
- H Hydrogen × 296.58%1.008 × 29 = 29.232 g/mol
- F Fluorine × 14.27%18.998 × 1 = 18.998 g/mol
- N Nitrogen × 412.60%14.007 × 4 = 56.028 g/mol
- O Oxygen × 13.60%15.999 × 1 = 15.999 g/mol
Compounds with the formula C27H29FN4O
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 4 of 4 compounds
Frequently asked questions
What is the molar mass of C27H29FN4O?
The molar mass of C27H29FN4O is 444.55 g/mol, calculated from standard atomic weights for 27 carbon atoms, 29 hydrogen atoms, 1 fluorine atom, 4 nitrogen atoms and 1 oxygen atom. The monoisotopic mass is 444.2325 Da.
How many compounds have the formula C27H29FN4O?
CompoundList lists 4 compounds with the molecular formula C27H29FN4O, including Desmethylastemizole, DC-PRC2in-01, Pde1-IN-5. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C27H29FN4O?
C27H29FN4O has a degree of unsaturation of 15. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.