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Molecular formula

C27H32FN5O2

4 compounds have this formula on CompoundList.

Molar mass
477.58g/mol
Monoisotopic mass
477.2540Da
Atoms
67
Elements
5
Rings plus double bonds
14

The formula C27H32FN5O2 describes a molecule made of 27 carbon atoms, 32 hydrogen atoms, 1 fluorine atom, 5 nitrogen atoms and 2 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 2767.90%
    12.011 × 27 = 324.297 g/mol
  • H Hydrogen × 326.75%
    1.008 × 32 = 32.256 g/mol
  • F Fluorine × 13.98%
    18.998 × 1 = 18.998 g/mol
  • N Nitrogen × 514.66%
    14.007 × 5 = 70.035 g/mol
  • O Oxygen × 26.70%
    15.999 × 2 = 31.998 g/mol
Look up another formula

Compounds with the formula C27H32FN5O2

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 4 of 4 compounds

Azd-1390 chemical structure, C27H32FN5O2, CAS 2089288-03-7
Azd-1390
CAS 2089288-03-7C27H32FN5O2
Azd-1390 C-11 chemical structure, C27H32FN5O2, CAS 2602521-34-4
Azd-1390 C-11
CAS 2602521-34-4C27H32FN5O2
7-Benzyl-1-(4-fluorophenyl)-8-methyl-3-(3-morpholinopropyl)-1,2,3,4-tetrahydro-6H-pyrimido[1,2-a][1,3,5]triazin-6-one chemical structure, C27H32FN5O2, CAS 1158319-35-7
7-Benzyl-1-(4-fluorophenyl)-8-methyl-3-(3-morpholinopropyl)-1,2,3,4-tetrahydro-6H-pyrimido[1,2-a][1,3,5]triazin-6-one
CAS 1158319-35-7C27H32FN5O2
N-[3-[[[2-(Diethylamino)ethyl]amino]carbonyl]phenyl]-1-(4-fluorophenyl)-4,5,6,7-tetrahydro-1H-indazole-3-carboxamide chemical structure, C27H32FN5O2, CAS 1208400-74-1
N-[3-[[[2-(Diethylamino)ethyl]amino]carbonyl]phenyl]-1-(4-fluorophenyl)-4,5,6,7-tetrahydro-1H-indazole-3-carboxamide
CAS 1208400-74-1C27H32FN5O2

Frequently asked questions

What is the molar mass of C27H32FN5O2?

The molar mass of C27H32FN5O2 is 477.58 g/mol, calculated from standard atomic weights for 27 carbon atoms, 32 hydrogen atoms, 1 fluorine atom, 5 nitrogen atoms and 2 oxygen atoms. The monoisotopic mass is 477.2540 Da.

How many compounds have the formula C27H32FN5O2?

CompoundList lists 4 compounds with the molecular formula C27H32FN5O2, including Azd-1390, Azd-1390 C-11, 7-Benzyl-1-(4-fluorophenyl)-8-methyl-3-(3-morpholinopropyl)-1,2,3,4-tetrahydro-6H-pyrimido[1,2-a][1,3,5]triazin-6-one. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C27H32FN5O2?

C27H32FN5O2 has a degree of unsaturation of 14. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.