C27H32N4
5 compounds have this formula on CompoundList.
- Molar mass
- 412.58g/mol
- Monoisotopic mass
- 412.2627Da
- Atoms
- 63
- Elements
- 3
- Rings plus double bonds
- 14
The formula C27H32N4 describes a molecule made of 27 carbon atoms, 32 hydrogen atoms and 4 nitrogen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 2778.60%12.011 × 27 = 324.297 g/mol
- H Hydrogen × 327.82%1.008 × 32 = 32.256 g/mol
- N Nitrogen × 413.58%14.007 × 4 = 56.028 g/mol
Compounds with the formula C27H32N4
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 5 of 5 compounds
![5-tert-Butyl-N-(4-butylphenyl)-2-methyl-3-phenylpyrazolo[1,5-a]pyrimidin-7-amine chemical structure, C27H32N4, CAS 850764-79-3](/s/YTCAUWSVXIKUHN-UHFFFAOYSA-N.svg)
Frequently asked questions
What is the molar mass of C27H32N4?
The molar mass of C27H32N4 is 412.58 g/mol, calculated from standard atomic weights for 27 carbon atoms, 32 hydrogen atoms and 4 nitrogen atoms. The monoisotopic mass is 412.2627 Da.
How many compounds have the formula C27H32N4?
CompoundList lists 5 compounds with the molecular formula C27H32N4, including Pcs1055, 1,9-Nonanediamine, N,N'-di-4-quinolinyl-, 5-tert-Butyl-N-(4-butylphenyl)-2-methyl-3-phenylpyrazolo[1,5-a]pyrimidin-7-amine. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C27H32N4?
C27H32N4 has a degree of unsaturation of 14. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.