C27H39Pr
1 compound has this formula on CompoundList.
- Molar mass
- 504.52g/mol
- Monoisotopic mass
- 504.2128Da
- Atoms
- 67
- Elements
- 3
The formula C27H39Pr describes a molecule made of 27 carbon atoms, 39 hydrogen atoms and 1 praseodymium atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 2764.28%12.011 × 27 = 324.297 g/mol
- H Hydrogen × 397.79%1.008 × 39 = 39.312 g/mol
- Pr Praseodymium × 127.93%140.91 × 1 = 140.910 g/mol
Compounds with the formula C27H39Pr
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C27H39Pr?
The molar mass of C27H39Pr is 504.52 g/mol, calculated from standard atomic weights for 27 carbon atoms, 39 hydrogen atoms and 1 praseodymium atom. The monoisotopic mass is 504.2128 Da.
How many compounds have the formula C27H39Pr?
CompoundList lists 1 compound with the molecular formula C27H39Pr, including Tris(tetramethylcyclopentadienyl)praseodymium(III). Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.