CompoundList
Molecular formula

C28H23F3N6

1 compound has this formula on CompoundList.

Molar mass
500.53g/mol
Monoisotopic mass
500.1936Da
Atoms
60
Elements
4
Rings plus double bonds
19

The formula C28H23F3N6 describes a molecule made of 28 carbon atoms, 23 hydrogen atoms, 3 fluorine atoms and 6 nitrogen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 2867.19%
    12.011 × 28 = 336.308 g/mol
  • H Hydrogen × 234.63%
    1.008 × 23 = 23.184 g/mol
  • F Fluorine × 311.39%
    18.998 × 3 = 56.994 g/mol
  • N Nitrogen × 616.79%
    14.007 × 6 = 84.042 g/mol
Look up another formula

Compounds with the formula C28H23F3N6

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 1 of 1 compounds

Frequently asked questions

What is the molar mass of C28H23F3N6?

The molar mass of C28H23F3N6 is 500.53 g/mol, calculated from standard atomic weights for 28 carbon atoms, 23 hydrogen atoms, 3 fluorine atoms and 6 nitrogen atoms. The monoisotopic mass is 500.1936 Da.

How many compounds have the formula C28H23F3N6?

CompoundList lists 1 compound with the molecular formula C28H23F3N6, including 3-Pyridinecarbonitrile, 4-methyl-2,6-bis[(4-methylphenyl)amino]-5-[2-[2-(trifluoromethyl)phenyl]diazenyl]-. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C28H23F3N6?

C28H23F3N6 has a degree of unsaturation of 19. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.