CompoundList
Molecular formula

C29H27N5O

9 compounds have this formula on CompoundList.

Molar mass
461.57g/mol
Monoisotopic mass
461.2216Da
Atoms
62
Elements
4
Rings plus double bonds
19

The formula C29H27N5O describes a molecule made of 29 carbon atoms, 27 hydrogen atoms, 5 nitrogen atoms and 1 oxygen atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 2975.46%
    12.011 × 29 = 348.319 g/mol
  • H Hydrogen × 275.90%
    1.008 × 27 = 27.216 g/mol
  • N Nitrogen × 515.17%
    14.007 × 5 = 70.035 g/mol
  • O Oxygen × 13.47%
    15.999 × 1 = 15.999 g/mol
Look up another formula

Compounds with the formula C29H27N5O

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 9 of 9 compounds

Frequently asked questions

What is the molar mass of C29H27N5O?

The molar mass of C29H27N5O is 461.57 g/mol, calculated from standard atomic weights for 29 carbon atoms, 27 hydrogen atoms, 5 nitrogen atoms and 1 oxygen atom. The monoisotopic mass is 461.2216 Da.

How many compounds have the formula C29H27N5O?

CompoundList lists 9 compounds with the molecular formula C29H27N5O, including Amg-548, 4-(tert-Butyl)-N-(3-(8-(phenylamino)imidazo[1,2-a]pyrazin-6-yl)phenyl)benzamide, GPR84 antagonist 3. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C29H27N5O?

C29H27N5O has a degree of unsaturation of 19. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.