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Molecular formula

C29H37N5O9

2 compounds have this formula on CompoundList.

Molar mass
599.64g/mol
Monoisotopic mass
599.2591Da
Atoms
80
Elements
4
Rings plus double bonds
14

The formula C29H37N5O9 describes a molecule made of 29 carbon atoms, 37 hydrogen atoms, 5 nitrogen atoms and 9 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 2958.09%
    12.011 × 29 = 348.319 g/mol
  • H Hydrogen × 376.22%
    1.008 × 37 = 37.296 g/mol
  • N Nitrogen × 511.68%
    14.007 × 5 = 70.035 g/mol
  • O Oxygen × 924.01%
    15.999 × 9 = 143.991 g/mol
Look up another formula

Compounds with the formula C29H37N5O9

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 2 of 2 compounds

Exorphin A5 chemical structure, C29H37N5O9, CAS 142155-24-6
Exorphin A5
CAS 142155-24-6C29H37N5O9
(4S)-4-([5-[1-(Ethoxycarbonyl)cyclobutoxy]-1-phenyl-1H-pyrazol-3-yl]formamido)-5-[4-(ethoxycarbonyl)piperazin-1-yl]-5-oxopentanoic acid chemical structure, C29H37N5O9, CAS 1164335-61-8
(4S)-4-([5-[1-(Ethoxycarbonyl)cyclobutoxy]-1-phenyl-1H-pyrazol-3-yl]formamido)-5-[4-(ethoxycarbonyl)piperazin-1-yl]-5-oxopentanoic acid
CAS 1164335-61-8C29H37N5O9

Frequently asked questions

What is the molar mass of C29H37N5O9?

The molar mass of C29H37N5O9 is 599.64 g/mol, calculated from standard atomic weights for 29 carbon atoms, 37 hydrogen atoms, 5 nitrogen atoms and 9 oxygen atoms. The monoisotopic mass is 599.2591 Da.

How many compounds have the formula C29H37N5O9?

CompoundList lists 2 compounds with the molecular formula C29H37N5O9, including Exorphin A5, (4S)-4-([5-[1-(Ethoxycarbonyl)cyclobutoxy]-1-phenyl-1H-pyrazol-3-yl]formamido)-5-[4-(ethoxycarbonyl)piperazin-1-yl]-5-oxopentanoic acid. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C29H37N5O9?

C29H37N5O9 has a degree of unsaturation of 14. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.