C30H31ClN4O7S
1 compound has this formula on CompoundList.
- Molar mass
- 627.11g/mol
- Monoisotopic mass
- 626.1602Da
- Atoms
- 74
- Elements
- 6
- Rings plus double bonds
- 17
The formula C30H31ClN4O7S describes a molecule made of 30 carbon atoms, 31 hydrogen atoms, 1 chlorine atom, 4 nitrogen atoms, 7 oxygen atoms and 1 sulfur atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 3057.46%12.011 × 30 = 360.330 g/mol
- H Hydrogen × 314.98%1.008 × 31 = 31.248 g/mol
- Cl Chlorine × 15.65%35.45 × 1 = 35.450 g/mol
- N Nitrogen × 48.93%14.007 × 4 = 56.028 g/mol
- O Oxygen × 717.86%15.999 × 7 = 111.993 g/mol
- S Sulfur × 15.11%32.06 × 1 = 32.060 g/mol
Compounds with the formula C30H31ClN4O7S
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C30H31ClN4O7S?
The molar mass of C30H31ClN4O7S is 627.11 g/mol, calculated from standard atomic weights for 30 carbon atoms, 31 hydrogen atoms, 1 chlorine atom, 4 nitrogen atoms, 7 oxygen atoms and 1 sulfur atom. The monoisotopic mass is 626.1602 Da.
How many compounds have the formula C30H31ClN4O7S?
CompoundList lists 1 compound with the molecular formula C30H31ClN4O7S, including Pigment Red 5. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C30H31ClN4O7S?
C30H31ClN4O7S has a degree of unsaturation of 17. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.