CompoundList
Molecular formula

C31H30FN3O7

1 compound has this formula on CompoundList.

Molar mass
575.59g/mol
Monoisotopic mass
575.2068Da
Atoms
72
Elements
5
Rings plus double bonds
18

The formula C31H30FN3O7 describes a molecule made of 31 carbon atoms, 30 hydrogen atoms, 1 fluorine atom, 3 nitrogen atoms and 7 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 3164.69%
    12.011 × 31 = 372.341 g/mol
  • H Hydrogen × 305.25%
    1.008 × 30 = 30.240 g/mol
  • F Fluorine × 13.30%
    18.998 × 1 = 18.998 g/mol
  • N Nitrogen × 37.30%
    14.007 × 3 = 42.021 g/mol
  • O Oxygen × 719.46%
    15.999 × 7 = 111.993 g/mol
Look up another formula

Compounds with the formula C31H30FN3O7

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 1 of 1 compounds

Frequently asked questions

What is the molar mass of C31H30FN3O7?

The molar mass of C31H30FN3O7 is 575.59 g/mol, calculated from standard atomic weights for 31 carbon atoms, 30 hydrogen atoms, 1 fluorine atom, 3 nitrogen atoms and 7 oxygen atoms. The monoisotopic mass is 575.2068 Da.

How many compounds have the formula C31H30FN3O7?

CompoundList lists 1 compound with the molecular formula C31H30FN3O7, including 4-{4-[(4-Fluorobenzyl)oxy]benzoyl}-3-hydroxy-1-[3-(4-morpholinyl)propyl]-5-(4-nitrophenyl)-1,5-dihydro-2H-pyrrol-2-one. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C31H30FN3O7?

C31H30FN3O7 has a degree of unsaturation of 18. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.