C32H28F3N5O4
3 compounds have this formula on CompoundList.
- Molar mass
- 603.60g/mol
- Monoisotopic mass
- 603.2093Da
- Atoms
- 72
- Elements
- 5
- Rings plus double bonds
- 20
The formula C32H28F3N5O4 describes a molecule made of 32 carbon atoms, 28 hydrogen atoms, 3 fluorine atoms, 5 nitrogen atoms and 4 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 3263.68%12.011 × 32 = 384.352 g/mol
- H Hydrogen × 284.68%1.008 × 28 = 28.224 g/mol
- F Fluorine × 39.44%18.998 × 3 = 56.994 g/mol
- N Nitrogen × 511.60%14.007 × 5 = 70.035 g/mol
- O Oxygen × 410.60%15.999 × 4 = 63.996 g/mol
Compounds with the formula C32H28F3N5O4
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 3 of 3 compounds
Frequently asked questions
What is the molar mass of C32H28F3N5O4?
The molar mass of C32H28F3N5O4 is 603.60 g/mol, calculated from standard atomic weights for 32 carbon atoms, 28 hydrogen atoms, 3 fluorine atoms, 5 nitrogen atoms and 4 oxygen atoms. The monoisotopic mass is 603.2093 Da.
How many compounds have the formula C32H28F3N5O4?
CompoundList lists 3 compounds with the molecular formula C32H28F3N5O4, including (Inverted exclamation markA)-AMG 487, Amg-487, AMG 487 (S-enantiomer). Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C32H28F3N5O4?
C32H28F3N5O4 has a degree of unsaturation of 20. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.