CompoundList
Molecular formula

C32H30F5N3O5

4 compounds have this formula on CompoundList.

Molar mass
631.60g/mol
Monoisotopic mass
631.2106Da
Atoms
75
Elements
5
Rings plus double bonds
17

The formula C32H30F5N3O5 describes a molecule made of 32 carbon atoms, 30 hydrogen atoms, 5 fluorine atoms, 3 nitrogen atoms and 5 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 3260.85%
    12.011 × 32 = 384.352 g/mol
  • H Hydrogen × 304.79%
    1.008 × 30 = 30.240 g/mol
  • F Fluorine × 515.04%
    18.998 × 5 = 94.990 g/mol
  • N Nitrogen × 36.65%
    14.007 × 3 = 42.021 g/mol
  • O Oxygen × 512.67%
    15.999 × 5 = 79.995 g/mol
Look up another formula

Compounds with the formula C32H30F5N3O5

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 4 of 4 compounds

Frequently asked questions

What is the molar mass of C32H30F5N3O5?

The molar mass of C32H30F5N3O5 is 631.60 g/mol, calculated from standard atomic weights for 32 carbon atoms, 30 hydrogen atoms, 5 fluorine atoms, 3 nitrogen atoms and 5 oxygen atoms. The monoisotopic mass is 631.2106 Da.

How many compounds have the formula C32H30F5N3O5?

CompoundList lists 4 compounds with the molecular formula C32H30F5N3O5, including Elagolix, 4-[[2-[5-(2-Fluoro-3-methoxyphenyl)-3-[[2-fluoro-6-(trifluoromethyl)phenyl]methyl]-4-methyl-2,6-dioxopyrimidin-1-yl]-1-phenylethyl]amino]butanoic acid, (S)-Elagolix. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C32H30F5N3O5?

C32H30F5N3O5 has a degree of unsaturation of 17. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.