C34H28Br2N4
1 compound has this formula on CompoundList.
- Molar mass
- 652.43g/mol
- Monoisotopic mass
- 650.0681Da
- Atoms
- 68
- Elements
- 4
- Rings plus double bonds
- 22
The formula C34H28Br2N4 describes a molecule made of 34 carbon atoms, 28 hydrogen atoms, 2 bromine atoms and 4 nitrogen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 3462.59%12.011 × 34 = 408.374 g/mol
- H Hydrogen × 284.33%1.008 × 28 = 28.224 g/mol
- Br Bromine × 224.49%79.904 × 2 = 159.808 g/mol
- N Nitrogen × 48.59%14.007 × 4 = 56.028 g/mol
Compounds with the formula C34H28Br2N4
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C34H28Br2N4?
The molar mass of C34H28Br2N4 is 652.43 g/mol, calculated from standard atomic weights for 34 carbon atoms, 28 hydrogen atoms, 2 bromine atoms and 4 nitrogen atoms. The monoisotopic mass is 650.0681 Da.
How many compounds have the formula C34H28Br2N4?
CompoundList lists 1 compound with the molecular formula C34H28Br2N4, including 1,1'-(Biphenyl-4,4'-diylbis(methylene))bis(4,4'-bipyridinium) Dibromide. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C34H28Br2N4?
C34H28Br2N4 has a degree of unsaturation of 22. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.