C34H71O8P
2 compounds have this formula on CompoundList.
- Molar mass
- 638.91g/mol
- Monoisotopic mass
- 638.4887Da
- Atoms
- 114
- Elements
- 4
- Rings plus double bonds
- 0
The formula C34H71O8P describes a molecule made of 34 carbon atoms, 71 hydrogen atoms, 8 oxygen atoms and 1 phosphorus atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 3463.92%12.011 × 34 = 408.374 g/mol
- H Hydrogen × 7111.20%1.008 × 71 = 71.568 g/mol
- O Oxygen × 820.03%15.999 × 8 = 127.992 g/mol
- P Phosphorus × 14.85%30.974 × 1 = 30.974 g/mol
Compounds with the formula C34H71O8P
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 2 of 2 compounds
![Ethanol, 2-[2-(tridecyloxy)ethoxy]-, 1,1'-(hydrogen phosphate) chemical structure, C34H71O8P, CAS 65087-01-6](/s/FGSBZAZJWFNVCX-UHFFFAOYSA-N.svg)
Frequently asked questions
What is the molar mass of C34H71O8P?
The molar mass of C34H71O8P is 638.91 g/mol, calculated from standard atomic weights for 34 carbon atoms, 71 hydrogen atoms, 8 oxygen atoms and 1 phosphorus atom. The monoisotopic mass is 638.4887 Da.
How many compounds have the formula C34H71O8P?
CompoundList lists 2 compounds with the molecular formula C34H71O8P, including Cetearyl phosphate, Ethanol, 2-[2-(tridecyloxy)ethoxy]-, 1,1'-(hydrogen phosphate). Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C34H71O8P?
C34H71O8P has a degree of unsaturation of 0. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.