C35H32F6N6O2PRu
1 compound has this formula on CompoundList.
- Molar mass
- 814.71g/mol
- Monoisotopic mass
- 815.1272Da
- Atoms
- 83
- Elements
- 7
The formula C35H32F6N6O2PRu describes a molecule made of 35 carbon atoms, 32 hydrogen atoms, 6 fluorine atoms, 6 nitrogen atoms, 2 oxygen atoms, 1 phosphorus atom and 1 ruthenium atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 3551.60%12.011 × 35 = 420.385 g/mol
- H Hydrogen × 323.96%1.008 × 32 = 32.256 g/mol
- F Fluorine × 613.99%18.998 × 6 = 113.988 g/mol
- N Nitrogen × 610.32%14.007 × 6 = 84.042 g/mol
- O Oxygen × 23.93%15.999 × 2 = 31.998 g/mol
- P Phosphorus × 13.80%30.974 × 1 = 30.974 g/mol
- Ru Ruthenium × 112.41%101.07 × 1 = 101.070 g/mol
Compounds with the formula C35H32F6N6O2PRu
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C35H32F6N6O2PRu?
The molar mass of C35H32F6N6O2PRu is 814.71 g/mol, calculated from standard atomic weights for 35 carbon atoms, 32 hydrogen atoms, 6 fluorine atoms, 6 nitrogen atoms, 2 oxygen atoms, 1 phosphorus atom and 1 ruthenium atom. The monoisotopic mass is 815.1272 Da.
How many compounds have the formula C35H32F6N6O2PRu?
CompoundList lists 1 compound with the molecular formula C35H32F6N6O2PRu, including RefChem:884024. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.