CompoundList
Molecular formula

C39H24IrN3S3

1 compound has this formula on CompoundList.

Molar mass
823.04g/mol
Monoisotopic mass
823.0762Da
Atoms
70
Elements
5

The formula C39H24IrN3S3 describes a molecule made of 39 carbon atoms, 24 hydrogen atoms, 1 iridium atom, 3 nitrogen atoms and 3 sulfur atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 3956.91%
    12.011 × 39 = 468.429 g/mol
  • H Hydrogen × 242.94%
    1.008 × 24 = 24.192 g/mol
  • Ir Iridium × 123.35%
    192.22 × 1 = 192.220 g/mol
  • N Nitrogen × 35.11%
    14.007 × 3 = 42.021 g/mol
  • S Sulfur × 311.69%
    32.06 × 3 = 96.180 g/mol
Look up another formula

Compounds with the formula C39H24IrN3S3

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 1 of 1 compounds

Frequently asked questions

What is the molar mass of C39H24IrN3S3?

The molar mass of C39H24IrN3S3 is 823.04 g/mol, calculated from standard atomic weights for 39 carbon atoms, 24 hydrogen atoms, 1 iridium atom, 3 nitrogen atoms and 3 sulfur atoms. The monoisotopic mass is 823.0762 Da.

How many compounds have the formula C39H24IrN3S3?

CompoundList lists 1 compound with the molecular formula C39H24IrN3S3, including Fac-Tris[2-(benzo[b]thiophen-2-yl)pyridinato-C3,N]iridium(III). Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.