C39H27N3
9 compounds have this formula on CompoundList.
- Molar mass
- 537.67g/mol
- Monoisotopic mass
- 537.2205Da
- Atoms
- 69
- Elements
- 3
- Rings plus double bonds
- 28
The formula C39H27N3 describes a molecule made of 39 carbon atoms, 27 hydrogen atoms and 3 nitrogen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 3987.12%12.011 × 39 = 468.429 g/mol
- H Hydrogen × 275.06%1.008 × 27 = 27.216 g/mol
- N Nitrogen × 37.82%14.007 × 3 = 42.021 g/mol
Compounds with the formula C39H27N3
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 9 of 9 compounds
Frequently asked questions
What is the molar mass of C39H27N3?
The molar mass of C39H27N3 is 537.67 g/mol, calculated from standard atomic weights for 39 carbon atoms, 27 hydrogen atoms and 3 nitrogen atoms. The monoisotopic mass is 537.2205 Da.
How many compounds have the formula C39H27N3?
CompoundList lists 9 compounds with the molecular formula C39H27N3, including 4,4',4''-Tris[(3-methylphenyl)phenylamino]triphenylamine, Tris-biphenyl triazine, 1,3,5-Tri(p-pyrid-3-ylphenyl)benzene. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C39H27N3?
C39H27N3 has a degree of unsaturation of 28. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.