C3H3B10Br
1 compound has this formula on CompoundList.
- Molar mass
- 227.06g/mol
- Monoisotopic mass
- 228.0349Da
- Atoms
- 17
- Elements
- 4
The formula C3H3B10Br describes a molecule made of 3 carbon atoms, 3 hydrogen atoms, 10 boron atoms and 1 bromine atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 315.87%12.011 × 3 = 36.033 g/mol
- H Hydrogen × 31.33%1.008 × 3 = 3.024 g/mol
- B Boron × 1047.61%10.81 × 10 = 108.100 g/mol
- Br Bromine × 135.19%79.904 × 1 = 79.904 g/mol
Compounds with the formula C3H3B10Br
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C3H3B10Br?
The molar mass of C3H3B10Br is 227.06 g/mol, calculated from standard atomic weights for 3 carbon atoms, 3 hydrogen atoms, 10 boron atoms and 1 bromine atom. The monoisotopic mass is 228.0349 Da.
How many compounds have the formula C3H3B10Br?
CompoundList lists 1 compound with the molecular formula C3H3B10Br, including 1-Bromomethyl-1,2-dicarba-closo-dodecaborane(12). Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.