C3H5ClF3N
2 compounds have this formula on CompoundList.
- Molar mass
- 147.52g/mol
- Monoisotopic mass
- 147.0063Da
- Atoms
- 13
- Elements
- 5
- Rings plus double bonds
- 0
The formula C3H5ClF3N describes a molecule made of 3 carbon atoms, 5 hydrogen atoms, 1 chlorine atom, 3 fluorine atoms and 1 nitrogen atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 324.43%12.011 × 3 = 36.033 g/mol
- H Hydrogen × 53.42%1.008 × 5 = 5.040 g/mol
- Cl Chlorine × 124.03%35.45 × 1 = 35.450 g/mol
- F Fluorine × 338.63%18.998 × 3 = 56.994 g/mol
- N Nitrogen × 19.49%14.007 × 1 = 14.007 g/mol
Compounds with the formula C3H5ClF3N
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 2 of 2 compounds
Frequently asked questions
What is the molar mass of C3H5ClF3N?
The molar mass of C3H5ClF3N is 147.52 g/mol, calculated from standard atomic weights for 3 carbon atoms, 5 hydrogen atoms, 1 chlorine atom, 3 fluorine atoms and 1 nitrogen atom. The monoisotopic mass is 147.0063 Da.
How many compounds have the formula C3H5ClF3N?
CompoundList lists 2 compounds with the molecular formula C3H5ClF3N, including 2,3,3-Trifluoroprop-2-en-1-amine hydrochloride, 2-Chloro-3,3,3-trifluoropropan-1-amine. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C3H5ClF3N?
C3H5ClF3N has a degree of unsaturation of 0. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.