C3H5F3OS
3 compounds have this formula on CompoundList.
- Molar mass
- 146.13g/mol
- Monoisotopic mass
- 146.0013Da
- Atoms
- 13
- Elements
- 5
- Rings plus double bonds
- 0
The formula C3H5F3OS describes a molecule made of 3 carbon atoms, 5 hydrogen atoms, 3 fluorine atoms, 1 oxygen atom and 1 sulfur atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 324.66%12.011 × 3 = 36.033 g/mol
- H Hydrogen × 53.45%1.008 × 5 = 5.040 g/mol
- F Fluorine × 339.00%18.998 × 3 = 56.994 g/mol
- O Oxygen × 110.95%15.999 × 1 = 15.999 g/mol
- S Sulfur × 121.94%32.06 × 1 = 32.060 g/mol
Compounds with the formula C3H5F3OS
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 3 of 3 compounds
Frequently asked questions
What is the molar mass of C3H5F3OS?
The molar mass of C3H5F3OS is 146.13 g/mol, calculated from standard atomic weights for 3 carbon atoms, 5 hydrogen atoms, 3 fluorine atoms, 1 oxygen atom and 1 sulfur atom. The monoisotopic mass is 146.0013 Da.
How many compounds have the formula C3H5F3OS?
CompoundList lists 3 compounds with the molecular formula C3H5F3OS, including 2-(Trifluoromethylsulfanyl)ethanol, 2-(Trifluoromethoxy)ethanethiol, 2,2-Difluoropropane-1-sulfinyl fluoride. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C3H5F3OS?
C3H5F3OS has a degree of unsaturation of 0. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.