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Molecular formula

C40H18BF20I

1 compound has this formula on CompoundList.

Molar mass
1016.25g/mol
Monoisotopic mass
1016.0227Da
Atoms
80
Elements
5

The formula C40H18BF20I describes a molecule made of 40 carbon atoms, 18 hydrogen atoms, 1 boron atom, 20 fluorine atoms and 1 iodine atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 4047.28%
    12.011 × 40 = 480.440 g/mol
  • H Hydrogen × 181.79%
    1.008 × 18 = 18.144 g/mol
  • B Boron × 11.06%
    10.81 × 1 = 10.810 g/mol
  • F Fluorine × 2037.39%
    18.998 × 20 = 379.960 g/mol
  • I Iodine × 112.49%
    126.9 × 1 = 126.900 g/mol
Look up another formula

Compounds with the formula C40H18BF20I

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 1 of 1 compounds

Iodonium, (4-(1-methylethyl)phenyl)(4-methylphenyl)-, tetrakis(2,3,4,5,6-pentafluorophenyl)borate(1-) (1:1) chemical structure, C40H18BF20I, CAS 178233-72-2
Iodonium, (4-(1-methylethyl)phenyl)(4-methylphenyl)-, tetrakis(2,3,4,5,6-pentafluorophenyl)borate(1-) (1:1)
CAS 178233-72-2C40H18BF20I

Frequently asked questions

What is the molar mass of C40H18BF20I?

The molar mass of C40H18BF20I is 1016.25 g/mol, calculated from standard atomic weights for 40 carbon atoms, 18 hydrogen atoms, 1 boron atom, 20 fluorine atoms and 1 iodine atom. The monoisotopic mass is 1016.0227 Da.

How many compounds have the formula C40H18BF20I?

CompoundList lists 1 compound with the molecular formula C40H18BF20I, including Iodonium, (4-(1-methylethyl)phenyl)(4-methylphenyl)-, tetrakis(2,3,4,5,6-pentafluorophenyl)borate(1-) (1:1). Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.