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Molecular formula

C40H24F2N2O4

1 compound has this formula on CompoundList.

Molar mass
634.64g/mol
Monoisotopic mass
634.1704Da
Atoms
72
Elements
5
Rings plus double bonds
29

The formula C40H24F2N2O4 describes a molecule made of 40 carbon atoms, 24 hydrogen atoms, 2 fluorine atoms, 2 nitrogen atoms and 4 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 4075.70%
    12.011 × 40 = 480.440 g/mol
  • H Hydrogen × 243.81%
    1.008 × 24 = 24.192 g/mol
  • F Fluorine × 25.99%
    18.998 × 2 = 37.996 g/mol
  • N Nitrogen × 24.41%
    14.007 × 2 = 28.014 g/mol
  • O Oxygen × 410.08%
    15.999 × 4 = 63.996 g/mol
Look up another formula

Compounds with the formula C40H24F2N2O4

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 1 of 1 compounds

Anthra[2,1,9-def:6,5,10-d'e'f']diisoquinoline-1,3,8,10(2H,9H)-tetrone, 2,9-bis[2-(4-fluorophenyl)ethyl]- chemical structure, C40H24F2N2O4, CAS 215726-57-1
Anthra[2,1,9-def:6,5,10-d'e'f']diisoquinoline-1,3,8,10(2H,9H)-tetrone, 2,9-bis[2-(4-fluorophenyl)ethyl]-
CAS 215726-57-1C40H24F2N2O4

Frequently asked questions

What is the molar mass of C40H24F2N2O4?

The molar mass of C40H24F2N2O4 is 634.64 g/mol, calculated from standard atomic weights for 40 carbon atoms, 24 hydrogen atoms, 2 fluorine atoms, 2 nitrogen atoms and 4 oxygen atoms. The monoisotopic mass is 634.1704 Da.

How many compounds have the formula C40H24F2N2O4?

CompoundList lists 1 compound with the molecular formula C40H24F2N2O4, including Anthra[2,1,9-def:6,5,10-d'e'f']diisoquinoline-1,3,8,10(2H,9H)-tetrone, 2,9-bis[2-(4-fluorophenyl)ethyl]-. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C40H24F2N2O4?

C40H24F2N2O4 has a degree of unsaturation of 29. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.