CompoundList
Molecular formula

C40H28B2F8O2

1 compound has this formula on CompoundList.

Molar mass
714.27g/mol
Monoisotopic mass
714.2148Da
Atoms
80
Elements
5

The formula C40H28B2F8O2 describes a molecule made of 40 carbon atoms, 28 hydrogen atoms, 2 boron atoms, 8 fluorine atoms and 2 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 4067.26%
    12.011 × 40 = 480.440 g/mol
  • H Hydrogen × 283.95%
    1.008 × 28 = 28.224 g/mol
  • B Boron × 23.03%
    10.81 × 2 = 21.620 g/mol
  • F Fluorine × 821.28%
    18.998 × 8 = 151.984 g/mol
  • O Oxygen × 24.48%
    15.999 × 2 = 31.998 g/mol
Look up another formula

Compounds with the formula C40H28B2F8O2

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 1 of 1 compounds

Frequently asked questions

What is the molar mass of C40H28B2F8O2?

The molar mass of C40H28B2F8O2 is 714.27 g/mol, calculated from standard atomic weights for 40 carbon atoms, 28 hydrogen atoms, 2 boron atoms, 8 fluorine atoms and 2 oxygen atoms. The monoisotopic mass is 714.2148 Da.

How many compounds have the formula C40H28B2F8O2?

CompoundList lists 1 compound with the molecular formula C40H28B2F8O2, including 1,4-Phenylene-4,4'-bis(2,6-diphenyl-4-pyrylium tetrafluoroborate). Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.