CompoundList
Molecular formula

C40H37N3O5

2 compounds have this formula on CompoundList.

Molar mass
639.75g/mol
Monoisotopic mass
639.2733Da
Atoms
85
Elements
4
Rings plus double bonds
24

The formula C40H37N3O5 describes a molecule made of 40 carbon atoms, 37 hydrogen atoms, 3 nitrogen atoms and 5 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 4075.10%
    12.011 × 40 = 480.440 g/mol
  • H Hydrogen × 375.83%
    1.008 × 37 = 37.296 g/mol
  • N Nitrogen × 36.57%
    14.007 × 3 = 42.021 g/mol
  • O Oxygen × 512.50%
    15.999 × 5 = 79.995 g/mol
Look up another formula

Compounds with the formula C40H37N3O5

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 2 of 2 compounds

Frequently asked questions

What is the molar mass of C40H37N3O5?

The molar mass of C40H37N3O5 is 639.75 g/mol, calculated from standard atomic weights for 40 carbon atoms, 37 hydrogen atoms, 3 nitrogen atoms and 5 oxygen atoms. The monoisotopic mass is 639.2733 Da.

How many compounds have the formula C40H37N3O5?

CompoundList lists 2 compounds with the molecular formula C40H37N3O5, including Dibenzyl 4-[3-(4-ethoxyphenyl)-1-phenyl-1H-pyrazol-4-yl]-2,6-dimethyl-1,4-dihydro-3,5-pyridinedicarboxylate, 9H-Fluoren-9-ylmethyl N-[(1S)-1-[methoxy(methyl)carbamoyl]-2-[(triphenylmethyl)carbamoyl]ethyl]carbamate. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C40H37N3O5?

C40H37N3O5 has a degree of unsaturation of 24. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.