CompoundList
Molecular formula

C40H40N4O8

4 compounds have this formula on CompoundList.

Molar mass
704.78g/mol
Monoisotopic mass
704.2846Da
Atoms
92
Elements
4
Rings plus double bonds
23

The formula C40H40N4O8 describes a molecule made of 40 carbon atoms, 40 hydrogen atoms, 4 nitrogen atoms and 8 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 4068.17%
    12.011 × 40 = 480.440 g/mol
  • H Hydrogen × 405.72%
    1.008 × 40 = 40.320 g/mol
  • N Nitrogen × 47.95%
    14.007 × 4 = 56.028 g/mol
  • O Oxygen × 818.16%
    15.999 × 8 = 127.992 g/mol
Look up another formula

Compounds with the formula C40H40N4O8

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 4 of 4 compounds

Frequently asked questions

What is the molar mass of C40H40N4O8?

The molar mass of C40H40N4O8 is 704.78 g/mol, calculated from standard atomic weights for 40 carbon atoms, 40 hydrogen atoms, 4 nitrogen atoms and 8 oxygen atoms. The monoisotopic mass is 704.2846 Da.

How many compounds have the formula C40H40N4O8?

CompoundList lists 4 compounds with the molecular formula C40H40N4O8, including RefChem:488336, Bpd-DB, 23H,25H-Benzo[b]porphine-9,13-dipropanoic acid, 18-ethenyl-2,4a-dihydro-3,4-bis(methoxycarbonyl)-4a. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C40H40N4O8?

C40H40N4O8 has a degree of unsaturation of 23. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.