C40H58
9 compounds have this formula on CompoundList.
- Molar mass
- 538.90g/mol
- Monoisotopic mass
- 538.4539Da
- Atoms
- 98
- Elements
- 2
- Rings plus double bonds
- 12
The formula C40H58 describes a molecule made of 40 carbon atoms and 58 hydrogen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 4089.15%12.011 × 40 = 480.440 g/mol
- H Hydrogen × 5810.85%1.008 × 58 = 58.464 g/mol
Compounds with the formula C40H58
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 9 of 9 compounds
Frequently asked questions
What is the molar mass of C40H58?
The molar mass of C40H58 is 538.90 g/mol, calculated from standard atomic weights for 40 carbon atoms and 58 hydrogen atoms. The monoisotopic mass is 538.4539 Da.
How many compounds have the formula C40H58?
CompoundList lists 9 compounds with the molecular formula C40H58, including Neurosporene, beta-Zeacarotene, alpha-Zeacarotene. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C40H58?
C40H58 has a degree of unsaturation of 12. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.