CompoundList
Molecular formula

C40H58O4

15 compounds have this formula on CompoundList.

Molar mass
602.90g/mol
Monoisotopic mass
602.4335Da
Atoms
102
Elements
3
Rings plus double bonds
12

The formula C40H58O4 describes a molecule made of 40 carbon atoms, 58 hydrogen atoms and 4 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 4079.69%
    12.011 × 40 = 480.440 g/mol
  • H Hydrogen × 589.70%
    1.008 × 58 = 58.464 g/mol
  • O Oxygen × 410.61%
    15.999 × 4 = 63.996 g/mol
Look up another formula

Compounds with the formula C40H58O4

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 15 of 15 compounds

Frequently asked questions

What is the molar mass of C40H58O4?

The molar mass of C40H58O4 is 602.90 g/mol, calculated from standard atomic weights for 40 carbon atoms, 58 hydrogen atoms and 4 oxygen atoms. The monoisotopic mass is 602.4335 Da.

How many compounds have the formula C40H58O4?

CompoundList lists 15 compounds with the molecular formula C40H58O4, including gamma-Oryzanol, Cycloartenol ferulate, g-Oryzanol. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C40H58O4?

C40H58O4 has a degree of unsaturation of 12. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.