C40H64O8
2 compounds have this formula on CompoundList.
- Molar mass
- 672.94g/mol
- Monoisotopic mass
- 672.4601Da
- Atoms
- 112
- Elements
- 3
- Rings plus double bonds
- 9
The formula C40H64O8 describes a molecule made of 40 carbon atoms, 64 hydrogen atoms and 8 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 4071.39%12.011 × 40 = 480.440 g/mol
- H Hydrogen × 649.59%1.008 × 64 = 64.512 g/mol
- O Oxygen × 819.02%15.999 × 8 = 127.992 g/mol
Compounds with the formula C40H64O8
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 2 of 2 compounds
Frequently asked questions
What is the molar mass of C40H64O8?
The molar mass of C40H64O8 is 672.94 g/mol, calculated from standard atomic weights for 40 carbon atoms, 64 hydrogen atoms and 8 oxygen atoms. The monoisotopic mass is 672.4601 Da.
How many compounds have the formula C40H64O8?
CompoundList lists 2 compounds with the molecular formula C40H64O8, including Phorbol 12,13-didecanoate, 4alpha-Phorbol 12,13-didecanoate. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C40H64O8?
C40H64O8 has a degree of unsaturation of 9. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.