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Molecular formula

C41H50ClN3O8

1 compound has this formula on CompoundList.

Molar mass
748.31g/mol
Monoisotopic mass
747.3286Da
Atoms
103
Elements
5
Rings plus double bonds
18

The formula C41H50ClN3O8 describes a molecule made of 41 carbon atoms, 50 hydrogen atoms, 1 chlorine atom, 3 nitrogen atoms and 8 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 4165.81%
    12.011 × 41 = 492.451 g/mol
  • H Hydrogen × 506.74%
    1.008 × 50 = 50.400 g/mol
  • Cl Chlorine × 14.74%
    35.45 × 1 = 35.450 g/mol
  • N Nitrogen × 35.62%
    14.007 × 3 = 42.021 g/mol
  • O Oxygen × 817.10%
    15.999 × 8 = 127.992 g/mol
Look up another formula

Compounds with the formula C41H50ClN3O8

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 1 of 1 compounds

Benzoic acid, 4-chloro-3-[[2-[4-ethoxy-2,5-dioxo-3-(phenylmethyl)-1-imidazolidinyl]-3-(4-methoxyphenyl)-1,3-dioxopropyl]amino]-, dodecyl ester chemical structure, C41H50ClN3O8, CAS 70950-45-7
Benzoic acid, 4-chloro-3-[[2-[4-ethoxy-2,5-dioxo-3-(phenylmethyl)-1-imidazolidinyl]-3-(4-methoxyphenyl)-1,3-dioxopropyl]amino]-, dodecyl ester
CAS 70950-45-7C41H50ClN3O8

Frequently asked questions

What is the molar mass of C41H50ClN3O8?

The molar mass of C41H50ClN3O8 is 748.31 g/mol, calculated from standard atomic weights for 41 carbon atoms, 50 hydrogen atoms, 1 chlorine atom, 3 nitrogen atoms and 8 oxygen atoms. The monoisotopic mass is 747.3286 Da.

How many compounds have the formula C41H50ClN3O8?

CompoundList lists 1 compound with the molecular formula C41H50ClN3O8, including Benzoic acid, 4-chloro-3-[[2-[4-ethoxy-2,5-dioxo-3-(phenylmethyl)-1-imidazolidinyl]-3-(4-methoxyphenyl)-1,3-dioxopropyl]amino]-, dodecyl ester. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C41H50ClN3O8?

C41H50ClN3O8 has a degree of unsaturation of 18. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.