C42H71N9O17
1 compound has this formula on CompoundList.
- Molar mass
- 974.08g/mol
- Monoisotopic mass
- 973.4968Da
- Atoms
- 139
- Elements
- 4
- Rings plus double bonds
- 12
The formula C42H71N9O17 describes a molecule made of 42 carbon atoms, 71 hydrogen atoms, 9 nitrogen atoms and 17 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 4251.79%12.011 × 42 = 504.462 g/mol
- H Hydrogen × 717.35%1.008 × 71 = 71.568 g/mol
- N Nitrogen × 912.94%14.007 × 9 = 126.063 g/mol
- O Oxygen × 1727.92%15.999 × 17 = 271.983 g/mol
Compounds with the formula C42H71N9O17
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C42H71N9O17?
The molar mass of C42H71N9O17 is 974.08 g/mol, calculated from standard atomic weights for 42 carbon atoms, 71 hydrogen atoms, 9 nitrogen atoms and 17 oxygen atoms. The monoisotopic mass is 973.4968 Da.
How many compounds have the formula C42H71N9O17?
CompoundList lists 1 compound with the molecular formula C42H71N9O17, including Glomosporin. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C42H71N9O17?
C42H71N9O17 has a degree of unsaturation of 12. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.