C43H51BF4N2O2
1 compound has this formula on CompoundList.
- Molar mass
- 714.69g/mol
- Monoisotopic mass
- 714.3980Da
- Atoms
- 103
- Elements
- 6
The formula C43H51BF4N2O2 describes a molecule made of 43 carbon atoms, 51 hydrogen atoms, 1 boron atom, 4 fluorine atoms, 2 nitrogen atoms and 2 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 4372.26%12.011 × 43 = 516.473 g/mol
- H Hydrogen × 517.19%1.008 × 51 = 51.408 g/mol
- B Boron × 11.51%10.81 × 1 = 10.810 g/mol
- F Fluorine × 410.63%18.998 × 4 = 75.992 g/mol
- N Nitrogen × 23.92%14.007 × 2 = 28.014 g/mol
- O Oxygen × 24.48%15.999 × 2 = 31.998 g/mol
Compounds with the formula C43H51BF4N2O2
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C43H51BF4N2O2?
The molar mass of C43H51BF4N2O2 is 714.69 g/mol, calculated from standard atomic weights for 43 carbon atoms, 51 hydrogen atoms, 1 boron atom, 4 fluorine atoms, 2 nitrogen atoms and 2 oxygen atoms. The monoisotopic mass is 714.3980 Da.
How many compounds have the formula C43H51BF4N2O2?
CompoundList lists 1 compound with the molecular formula C43H51BF4N2O2, including 6-Butoxy-2-(5-(6-butoxy-1-butyl-1H-benzo(cd)indol-2-ylidene)-penta-1,3-dienyl)-1-butyl-benzo(cd)indolium tetrafluoroborate. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.