CompoundList
Molecular formula

C44H24Cl2F8Ir2N4

2 compounds have this formula on CompoundList.

Molar mass
1216.03g/mol
Monoisotopic mass
1216.0509Da
Atoms
84
Elements
6

The formula C44H24Cl2F8Ir2N4 describes a molecule made of 44 carbon atoms, 24 hydrogen atoms, 2 chlorine atoms, 8 fluorine atoms, 2 iridium atoms and 4 nitrogen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 4443.46%
    12.011 × 44 = 528.484 g/mol
  • H Hydrogen × 241.99%
    1.008 × 24 = 24.192 g/mol
  • Cl Chlorine × 25.83%
    35.45 × 2 = 70.900 g/mol
  • F Fluorine × 812.50%
    18.998 × 8 = 151.984 g/mol
  • Ir Iridium × 231.61%
    192.22 × 2 = 384.440 g/mol
  • N Nitrogen × 44.61%
    14.007 × 4 = 56.028 g/mol
Look up another formula

Compounds with the formula C44H24Cl2F8Ir2N4

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 2 of 2 compounds

Frequently asked questions

What is the molar mass of C44H24Cl2F8Ir2N4?

The molar mass of C44H24Cl2F8Ir2N4 is 1216.03 g/mol, calculated from standard atomic weights for 44 carbon atoms, 24 hydrogen atoms, 2 chlorine atoms, 8 fluorine atoms, 2 iridium atoms and 4 nitrogen atoms. The monoisotopic mass is 1216.0509 Da.

How many compounds have the formula C44H24Cl2F8Ir2N4?

CompoundList lists 2 compounds with the molecular formula C44H24Cl2F8Ir2N4, including di-mu-Chlorotetrakis[3,5-difluoro-2-(2-pyridinyl-kappan)phenyl-kappac]di-iridium, Di-mu-chlorotetrakis[3,5-difluoro-2-(2-pyridinyl-kappaN)phenyl-kappaC]diiridium. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.