CompoundList
Molecular formula

C48H59ClN12O8

1 compound has this formula on CompoundList.

Molar mass
967.53g/mol
Monoisotopic mass
966.4267Da
Atoms
128
Elements
5
Rings plus double bonds
25

The formula C48H59ClN12O8 describes a molecule made of 48 carbon atoms, 59 hydrogen atoms, 1 chlorine atom, 12 nitrogen atoms and 8 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 4859.59%
    12.011 × 48 = 576.528 g/mol
  • H Hydrogen × 596.15%
    1.008 × 59 = 59.472 g/mol
  • Cl Chlorine × 13.66%
    35.45 × 1 = 35.450 g/mol
  • N Nitrogen × 1217.37%
    14.007 × 12 = 168.084 g/mol
  • O Oxygen × 813.23%
    15.999 × 8 = 127.992 g/mol
Look up another formula

Compounds with the formula C48H59ClN12O8

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 1 of 1 compounds

Frequently asked questions

What is the molar mass of C48H59ClN12O8?

The molar mass of C48H59ClN12O8 is 967.53 g/mol, calculated from standard atomic weights for 48 carbon atoms, 59 hydrogen atoms, 1 chlorine atom, 12 nitrogen atoms and 8 oxygen atoms. The monoisotopic mass is 966.4267 Da.

How many compounds have the formula C48H59ClN12O8?

CompoundList lists 1 compound with the molecular formula C48H59ClN12O8, including Luteinizing Hormone-Releasing Hormone Antagonist trifluoroacetate salt. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C48H59ClN12O8?

C48H59ClN12O8 has a degree of unsaturation of 25. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.