CompoundList
Molecular formula

C49H55N9O7

5 compounds have this formula on CompoundList.

Molar mass
882.04g/mol
Monoisotopic mass
887.4601Da
Atoms
120
Elements
4
Rings plus double bonds
27

The formula C49H55N9O7 describes a molecule made of 49 carbon atoms, 55 hydrogen atoms, 9 nitrogen atoms and 7 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 4966.73%
    12.011 × 49 = 588.539 g/mol
  • H Hydrogen × 556.29%
    1.008 × 55 = 55.440 g/mol
  • N Nitrogen × 914.29%
    14.007 × 9 = 126.063 g/mol
  • O Oxygen × 712.70%
    15.999 × 7 = 111.993 g/mol
Look up another formula

Compounds with the formula C49H55N9O7

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 5 of 5 compounds

Frequently asked questions

What is the molar mass of C49H55N9O7?

The molar mass of C49H55N9O7 is 882.04 g/mol, calculated from standard atomic weights for 49 carbon atoms, 55 hydrogen atoms, 9 nitrogen atoms and 7 oxygen atoms. The monoisotopic mass is 887.4601 Da.

How many compounds have the formula C49H55N9O7?

CompoundList lists 5 compounds with the molecular formula C49H55N9O7, including Elbasvir, Bz-RGFFP-4M|ANA, Elbasvir, MK-8742, MK 8742, Elbasvir intermediate, Elbasvir-D6. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C49H55N9O7?

C49H55N9O7 has a degree of unsaturation of 27. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.