C49H58I4N6S2
1 compound has this formula on CompoundList.
- Molar mass
- 1302.76g/mol
- Monoisotopic mass
- 1302.0343Da
- Atoms
- 119
- Elements
- 5
- Rings plus double bonds
- 22
The formula C49H58I4N6S2 describes a molecule made of 49 carbon atoms, 58 hydrogen atoms, 4 iodine atoms, 6 nitrogen atoms and 2 sulfur atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 4945.18%12.011 × 49 = 588.539 g/mol
- H Hydrogen × 584.49%1.008 × 58 = 58.464 g/mol
- I Iodine × 438.96%126.9 × 4 = 507.600 g/mol
- N Nitrogen × 66.45%14.007 × 6 = 84.042 g/mol
- S Sulfur × 24.92%32.06 × 2 = 64.120 g/mol
Compounds with the formula C49H58I4N6S2
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C49H58I4N6S2?
The molar mass of C49H58I4N6S2 is 1302.76 g/mol, calculated from standard atomic weights for 49 carbon atoms, 58 hydrogen atoms, 4 iodine atoms, 6 nitrogen atoms and 2 sulfur atoms. The monoisotopic mass is 1302.0343 Da.
How many compounds have the formula C49H58I4N6S2?
CompoundList lists 1 compound with the molecular formula C49H58I4N6S2, including 1,1'-(4,4,7,7-Tetramethyl-4,7-diazaundecamethylene)-bis-4-(3-methyl-2,3-dihydro-(benzo-1,3-thiazole)-2-methylidene)-quinolinium tetraiodide. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C49H58I4N6S2?
C49H58I4N6S2 has a degree of unsaturation of 22. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.