C49H74O14
2 compounds have this formula on CompoundList.
- Molar mass
- 887.12g/mol
- Monoisotopic mass
- 886.5079Da
- Atoms
- 137
- Elements
- 3
- Rings plus double bonds
- 13
The formula C49H74O14 describes a molecule made of 49 carbon atoms, 74 hydrogen atoms and 14 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 4966.34%12.011 × 49 = 588.539 g/mol
- H Hydrogen × 748.41%1.008 × 74 = 74.592 g/mol
- O Oxygen × 1425.25%15.999 × 14 = 223.986 g/mol
Compounds with the formula C49H74O14
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 2 of 2 compounds
Frequently asked questions
What is the molar mass of C49H74O14?
The molar mass of C49H74O14 is 887.12 g/mol, calculated from standard atomic weights for 49 carbon atoms, 74 hydrogen atoms and 14 oxygen atoms. The monoisotopic mass is 886.5079 Da.
How many compounds have the formula C49H74O14?
CompoundList lists 2 compounds with the molecular formula C49H74O14, including Avermectin A1a, Avermectin A1. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C49H74O14?
C49H74O14 has a degree of unsaturation of 13. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.