C4F8I2
1 compound has this formula on CompoundList.
- Molar mass
- 453.83g/mol
- Monoisotopic mass
- 453.7962Da
- Atoms
- 14
- Elements
- 3
- Rings plus double bonds
- 0
The formula C4F8I2 describes a molecule made of 4 carbon atoms, 8 fluorine atoms and 2 iodine atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 410.59%12.011 × 4 = 48.044 g/mol
- F Fluorine × 833.49%18.998 × 8 = 151.984 g/mol
- I Iodine × 255.92%126.9 × 2 = 253.800 g/mol
Compounds with the formula C4F8I2
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C4F8I2?
The molar mass of C4F8I2 is 453.83 g/mol, calculated from standard atomic weights for 4 carbon atoms, 8 fluorine atoms and 2 iodine atoms. The monoisotopic mass is 453.7962 Da.
How many compounds have the formula C4F8I2?
CompoundList lists 1 compound with the molecular formula C4F8I2, including 1,1,2,2,3,3,4,4-Octafluoro-1,4-diiodobutane. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C4F8I2?
C4F8I2 has a degree of unsaturation of 0. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.