C4H9FO3S
9 compounds have this formula on CompoundList.
- Molar mass
- 156.17g/mol
- Monoisotopic mass
- 156.0256Da
- Atoms
- 18
- Elements
- 5
- Rings plus double bonds
- 0
The formula C4H9FO3S describes a molecule made of 4 carbon atoms, 9 hydrogen atoms, 1 fluorine atom, 3 oxygen atoms and 1 sulfur atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 430.76%12.011 × 4 = 48.044 g/mol
- H Hydrogen × 95.81%1.008 × 9 = 9.072 g/mol
- F Fluorine × 112.16%18.998 × 1 = 18.998 g/mol
- O Oxygen × 330.73%15.999 × 3 = 47.997 g/mol
- S Sulfur × 120.53%32.06 × 1 = 32.060 g/mol
Compounds with the formula C4H9FO3S
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 9 of 9 compounds
Frequently asked questions
What is the molar mass of C4H9FO3S?
The molar mass of C4H9FO3S is 156.17 g/mol, calculated from standard atomic weights for 4 carbon atoms, 9 hydrogen atoms, 1 fluorine atom, 3 oxygen atoms and 1 sulfur atom. The monoisotopic mass is 156.0256 Da.
How many compounds have the formula C4H9FO3S?
CompoundList lists 9 compounds with the molecular formula C4H9FO3S, including 2-Ethoxyethane-1-sulfonyl fluoride, 2-Hydroxy-2-methylpropane-1-sulfonyl fluoride, 3-Fluoropropyl methanesulfonate. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C4H9FO3S?
C4H9FO3S has a degree of unsaturation of 0. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.