CompoundList
Molecular formula

C50H84O21

2 compounds have this formula on CompoundList.

Molar mass
1021.20g/mol
Monoisotopic mass
1020.5505Da
Atoms
155
Elements
3
Rings plus double bonds
9

The formula C50H84O21 describes a molecule made of 50 carbon atoms, 84 hydrogen atoms and 21 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 5058.81%
    12.011 × 50 = 600.550 g/mol
  • H Hydrogen × 848.29%
    1.008 × 84 = 84.672 g/mol
  • O Oxygen × 2132.90%
    15.999 × 21 = 335.979 g/mol
Look up another formula

Compounds with the formula C50H84O21

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 2 of 2 compounds

Frequently asked questions

What is the molar mass of C50H84O21?

The molar mass of C50H84O21 is 1021.20 g/mol, calculated from standard atomic weights for 50 carbon atoms, 84 hydrogen atoms and 21 oxygen atoms. The monoisotopic mass is 1020.5505 Da.

How many compounds have the formula C50H84O21?

CompoundList lists 2 compounds with the molecular formula C50H84O21, including RefChem:922903, Scammonin VII. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C50H84O21?

C50H84O21 has a degree of unsaturation of 9. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.