CompoundList
Molecular formula

C51H64N4O12

2 compounds have this formula on CompoundList.

Molar mass
925.09g/mol
Monoisotopic mass
924.4521Da
Atoms
131
Elements
4
Rings plus double bonds
22

The formula C51H64N4O12 describes a molecule made of 51 carbon atoms, 64 hydrogen atoms, 4 nitrogen atoms and 12 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 5166.22%
    12.011 × 51 = 612.561 g/mol
  • H Hydrogen × 646.97%
    1.008 × 64 = 64.512 g/mol
  • N Nitrogen × 46.06%
    14.007 × 4 = 56.028 g/mol
  • O Oxygen × 1220.75%
    15.999 × 12 = 191.988 g/mol
Look up another formula

Compounds with the formula C51H64N4O12

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 2 of 2 compounds

Frequently asked questions

What is the molar mass of C51H64N4O12?

The molar mass of C51H64N4O12 is 925.09 g/mol, calculated from standard atomic weights for 51 carbon atoms, 64 hydrogen atoms, 4 nitrogen atoms and 12 oxygen atoms. The monoisotopic mass is 924.4521 Da.

How many compounds have the formula C51H64N4O12?

CompoundList lists 2 compounds with the molecular formula C51H64N4O12, including Vindolicine, Antibiotic T 9. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C51H64N4O12?

C51H64N4O12 has a degree of unsaturation of 22. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.