C54H104O7
3 compounds have this formula on CompoundList.
- Molar mass
- 865.42g/mol
- Monoisotopic mass
- 864.7782Da
- Atoms
- 165
- Elements
- 3
- Rings plus double bonds
- 3
The formula C54H104O7 describes a molecule made of 54 carbon atoms, 104 hydrogen atoms and 7 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 5474.95%12.011 × 54 = 648.594 g/mol
- H Hydrogen × 10412.11%1.008 × 104 = 104.832 g/mol
- O Oxygen × 712.94%15.999 × 7 = 111.993 g/mol
Compounds with the formula C54H104O7
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 3 of 3 compounds
Frequently asked questions
What is the molar mass of C54H104O7?
The molar mass of C54H104O7 is 865.42 g/mol, calculated from standard atomic weights for 54 carbon atoms, 104 hydrogen atoms and 7 oxygen atoms. The monoisotopic mass is 864.7782 Da.
How many compounds have the formula C54H104O7?
CompoundList lists 3 compounds with the molecular formula C54H104O7, including Trihexadecyl citrate, Triisocetyl citrate, Trihexyldecyl citrate. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C54H104O7?
C54H104O7 has a degree of unsaturation of 3. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.