C54H71N15O14
1 compound has this formula on CompoundList.
- Molar mass
- 1154.25g/mol
- Monoisotopic mass
- 1153.5305Da
- Atoms
- 154
- Elements
- 4
- Rings plus double bonds
- 27
The formula C54H71N15O14 describes a molecule made of 54 carbon atoms, 71 hydrogen atoms, 15 nitrogen atoms and 14 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 5456.19%12.011 × 54 = 648.594 g/mol
- H Hydrogen × 716.20%1.008 × 71 = 71.568 g/mol
- N Nitrogen × 1518.20%14.007 × 15 = 210.105 g/mol
- O Oxygen × 1419.41%15.999 × 14 = 223.986 g/mol
Compounds with the formula C54H71N15O14
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C54H71N15O14?
The molar mass of C54H71N15O14 is 1154.25 g/mol, calculated from standard atomic weights for 54 carbon atoms, 71 hydrogen atoms, 15 nitrogen atoms and 14 oxygen atoms. The monoisotopic mass is 1153.5305 Da.
How many compounds have the formula C54H71N15O14?
CompoundList lists 1 compound with the molecular formula C54H71N15O14, including LHRH, Gln(8)-. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C54H71N15O14?
C54H71N15O14 has a degree of unsaturation of 27. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.