C54H72F12N6P2Ru
1 compound has this formula on CompoundList.
- Molar mass
- 1196.21g/mol
- Monoisotopic mass
- 1196.4146Da
- Atoms
- 147
- Elements
- 6
The formula C54H72F12N6P2Ru describes a molecule made of 54 carbon atoms, 72 hydrogen atoms, 12 fluorine atoms, 6 nitrogen atoms, 2 phosphorus atoms and 1 ruthenium atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 5454.22%12.011 × 54 = 648.594 g/mol
- H Hydrogen × 726.07%1.008 × 72 = 72.576 g/mol
- F Fluorine × 1219.06%18.998 × 12 = 227.976 g/mol
- N Nitrogen × 67.03%14.007 × 6 = 84.042 g/mol
- P Phosphorus × 25.18%30.974 × 2 = 61.948 g/mol
- Ru Ruthenium × 18.45%101.07 × 1 = 101.070 g/mol
Compounds with the formula C54H72F12N6P2Ru
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
![Tris[4,4'-bis(t-butyl)-2,2'-bipyridine]ruthenium(II) hexafluorophosphate chemical structure, C54H72F12N6P2Ru, CAS 75777-87-6](/s/FTRGLDHRYZPEQS-UHFFFAOYSA-N.svg)
Frequently asked questions
What is the molar mass of C54H72F12N6P2Ru?
The molar mass of C54H72F12N6P2Ru is 1196.21 g/mol, calculated from standard atomic weights for 54 carbon atoms, 72 hydrogen atoms, 12 fluorine atoms, 6 nitrogen atoms, 2 phosphorus atoms and 1 ruthenium atom. The monoisotopic mass is 1196.4146 Da.
How many compounds have the formula C54H72F12N6P2Ru?
CompoundList lists 1 compound with the molecular formula C54H72F12N6P2Ru, including Tris[4,4'-bis(t-butyl)-2,2'-bipyridine]ruthenium(II) hexafluorophosphate. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.