CompoundList
Molecular formula

C54H92O24

18 compounds have this formula on CompoundList.

Molar mass
1125.31g/mol
Monoisotopic mass
1124.5979Da
Atoms
170
Elements
3
Rings plus double bonds
9

The formula C54H92O24 describes a molecule made of 54 carbon atoms, 92 hydrogen atoms and 24 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 5457.64%
    12.011 × 54 = 648.594 g/mol
  • H Hydrogen × 928.24%
    1.008 × 92 = 92.736 g/mol
  • O Oxygen × 2434.12%
    15.999 × 24 = 383.976 g/mol
Look up another formula

Compounds with the formula C54H92O24

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 18 of 18 compounds

Frequently asked questions

What is the molar mass of C54H92O24?

The molar mass of C54H92O24 is 1125.31 g/mol, calculated from standard atomic weights for 54 carbon atoms, 92 hydrogen atoms and 24 oxygen atoms. The monoisotopic mass is 1124.5979 Da.

How many compounds have the formula C54H92O24?

CompoundList lists 18 compounds with the molecular formula C54H92O24, including Mogroside IV, Siamenoside I, Mogroside IV-A. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C54H92O24?

C54H92O24 has a degree of unsaturation of 9. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.