CompoundList
Molecular formula

C55H97FN8O22S4

1 compound has this formula on CompoundList.

Molar mass
1369.65g/mol
Monoisotopic mass
1368.5584Da
Atoms
187
Elements
6
Rings plus double bonds
11

The formula C55H97FN8O22S4 describes a molecule made of 55 carbon atoms, 97 hydrogen atoms, 1 fluorine atom, 8 nitrogen atoms, 22 oxygen atoms and 4 sulfur atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 5548.23%
    12.011 × 55 = 660.605 g/mol
  • H Hydrogen × 977.14%
    1.008 × 97 = 97.776 g/mol
  • F Fluorine × 11.39%
    18.998 × 1 = 18.998 g/mol
  • N Nitrogen × 88.18%
    14.007 × 8 = 112.056 g/mol
  • O Oxygen × 2225.70%
    15.999 × 22 = 351.978 g/mol
  • S Sulfur × 49.36%
    32.06 × 4 = 128.240 g/mol
Look up another formula

Compounds with the formula C55H97FN8O22S4

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 1 of 1 compounds

Frequently asked questions

What is the molar mass of C55H97FN8O22S4?

The molar mass of C55H97FN8O22S4 is 1369.65 g/mol, calculated from standard atomic weights for 55 carbon atoms, 97 hydrogen atoms, 1 fluorine atom, 8 nitrogen atoms, 22 oxygen atoms and 4 sulfur atoms. The monoisotopic mass is 1368.5584 Da.

How many compounds have the formula C55H97FN8O22S4?

CompoundList lists 1 compound with the molecular formula C55H97FN8O22S4, including Oterna. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C55H97FN8O22S4?

C55H97FN8O22S4 has a degree of unsaturation of 11. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.